Spisak integrala racionalnih funkcija

Ovo je spisak integrala (antiderivativnih funkcija) racionalnih funkcija. Za kompletniji spisak integrala, pogledajte tabelu integrala i spisak integrala.

$\int (ax+b)^{n}dx$	$={\frac {(ax+b)^{n+1}}{a(n+1)}}\qquad {\mbox{(za }}n\neq -1{\mbox{)}}\,\!$
$\int {\frac {dx}{ax+b}}$	$={\frac {1}{a}}\ln \left|ax+b\right|$
$\int x(ax+b)^{n}dx$	$={\frac {a(n+1)x-b}{a^{2}(n+1)(n+2)}}(ax+b)^{n+1}\qquad {\mbox{(za }}n\not \in \{-1,-2\}{\mbox{)}}$

$\int {\frac {xdx}{ax+b}}$	$={\frac {x}{a}}-{\frac {b}{a^{2}}}\ln \left|ax+b\right|$
$\int {\frac {xdx}{(ax+b)^{2}}}$	$={\frac {b}{a^{2}(ax+b)}}+{\frac {1}{a^{2}}}\ln \left|ax+b\right|$
$\int {\frac {xdx}{(ax+b)^{n}}}$	$={\frac {a(1-n)x-b}{a^{2}(n-1)(n-2)(ax+b)^{n-1}}}\qquad {\mbox{(za }}n\not \in \{1,2\}{\mbox{)}}$

$\int {\frac {x^{2}dx}{ax+b}}$	$={\frac {1}{a^{3}}}\left({\frac {(ax+b)^{2}}{2}}-2b(ax+b)+b^{2}\ln \left|ax+b\right|\right)$
$\int {\frac {x^{2}dx}{(ax+b)^{2}}}$	$={\frac {1}{a^{3}}}\left(ax+b-2b\ln \left|ax+b\right|-{\frac {b^{2}}{ax+b}}\right)$
$\int {\frac {x^{2}dx}{(ax+b)^{3}}}$	$={\frac {1}{a^{3}}}\left(\ln \left|ax+b\right|+{\frac {2b}{ax+b}}-{\frac {b^{2}}{2(ax+b)^{2}}}\right)$
$\int {\frac {x^{2}dx}{(ax+b)^{n}}}$	$={\frac {1}{a^{3}}}\left(-{\frac {(ax+b)^{3-n}}{(n-3)}}+{\frac {2b(a+b)^{2-n}}{(n-2)}}-{\frac {b^{2}(ax+b)^{1-n}}{(n-1)}}\right)\qquad {\mbox{(za }}n\not \in \{1,2,3\}{\mbox{)}}$

$\int {\frac {dx}{x(ax+b)}}$	$=-{\frac {1}{b}}\ln \left|{\frac {ax+b}{x}}\right|$
$\int {\frac {dx}{x^{2}(ax+b)}}$	$=-{\frac {1}{bx}}+{\frac {a}{b^{2}}}\ln \left|{\frac {ax+b}{x}}\right|$
$\int {\frac {dx}{x^{2}(ax+b)^{2}}}$	$=-a\left({\frac {1}{b^{2}(ax+b)}}+{\frac {1}{ab^{2}x}}-{\frac {2}{b^{3}}}\ln \left|{\frac {ax+b}{x}}\right|\right)$
$\int {\frac {dx}{x^{2}+a^{2}}}$	$={\frac {1}{a}}\arctan {\frac {x}{a}}\,\!$
$\int {\frac {dx}{x^{2}-a^{2}}}=$	$-{\frac {1}{a}}\,\mathrm {arctanh} {\frac {x}{a}}={\frac {1}{2a}}\ln {\frac {a-x}{a+x}}\qquad {\mbox{(za }}|x|<|a|{\mbox{)}}\,\!$
	$-{\frac {1}{a}}\,\mathrm {arccoth} {\frac {x}{a}}={\frac {1}{2a}}\ln {\frac {x-a}{x+a}}\qquad {\mbox{(za }}|x|>|a|{\mbox{)}}\,\!$

$\int {\frac {dx}{ax^{2}+bx+c}}=$	${\frac {2}{\sqrt {4ac-b^{2}}}}\arctan {\frac {2ax+b}{\sqrt {4ac-b^{2}}}}\qquad {\mbox{(za }}4ac-b^{2}>0{\mbox{)}}$
	$-{\frac {2}{\sqrt {b^{2}-4ac}}}\,\mathrm {arctanh} {\frac {2ax+b}{\sqrt {b^{2}-4ac}}}={\frac {1}{\sqrt {b^{2}-4ac}}}\ln \left|{\frac {2ax+b-{\sqrt {b^{2}-4ac}}}{2ax+b+{\sqrt {b^{2}-4ac}}}}\right|\qquad {\mbox{(za }}4ac-b^{2}<0{\mbox{)}}$
	$-{\frac {2}{2ax+b}}\qquad {\mbox{(za }}4ac-b^{2}=0{\mbox{)}}$
$\int {\frac {xdx}{ax^{2}+bx+c}}$	$={\frac {1}{2a}}\ln \left|ax^{2}+bx+c\right|-{\frac {b}{2a}}\int {\frac {dx}{ax^{2}+bx+c}}$

$\int {\frac {(mx+n)dx}{ax^{2}+bx+c}}=$	${\frac {m}{2a}}\ln \left|ax^{2}+bx+c\right|+{\frac {2an-bm}{a{\sqrt {4ac-b^{2}}}}}\arctan {\frac {2ax+b}{\sqrt {4ac-b^{2}}}}\qquad {\mbox{(za }}4ac-b^{2}>0{\mbox{)}}$
	${\frac {m}{2a}}\ln \left|ax^{2}+bx+c\right|+{\frac {2an-bm}{a{\sqrt {b^{2}-4ac}}}}\,\mathrm {artanh} {\frac {2ax+b}{\sqrt {b^{2}-4ac}}}\qquad {\mbox{(za }}4ac-b^{2}<0{\mbox{)}}$
	${\frac {m}{2a}}\ln \left|ax^{2}+bx+c\right|-{\frac {2an-bm}{a(2ax+b)}}\,\,\,\,\,\,\,\,\,\,\qquad {\mbox{(za }}4ac-b^{2}=0{\mbox{)}}$

$\int {\frac {dx}{(ax^{2}+bx+c)^{n}}}={\frac {2ax+b}{(n-1)(4ac-b^{2})(ax^{2}+bx+c)^{n-1}}}+{\frac {(2n-3)2a}{(n-1)(4ac-b^{2})}}\int {\frac {dx}{(ax^{2}+bx+c)^{n-1}}}\,\!$

$\int {\frac {xdx}{(ax^{2}+bx+c)^{n}}}={\frac {bx+2c}{(n-1)(4ac-b^{2})(ax^{2}+bx+c)^{n-1}}}-{\frac {b(2n-3)}{(n-1)(4ac-b^{2})}}\int {\frac {dx}{(ax^{2}+bx+c)^{n-1}}}\,\!$

$\int {\frac {dx}{x(ax^{2}+bx+c)}}={\frac {1}{2c}}\ln \left|{\frac {x^{2}}{ax^{2}+bx+c}}\right|-{\frac {b}{2c}}\int {\frac {dx}{ax^{2}+bx+c}}$

Bilo koja racionalna funkcija se može integrisati koristeći gore navedene jednačine i parcijalne razlomke u integraciji, rastavljajući racionalnu funkciju na sumu razlomaka po formi:

${\frac {ex+f}{\left(ax^{2}+bx+c\right)^{n}}}$

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