Šablon:NumBlk

Dokumentacija šablona	[uredi] [historija] [osvježi keš]
Ova dokumentacija je prikazana u Šablon:NumBlk/dok.

Parametar

Parametri {{{1}}}, {{{2}}} i {{{3}}} ovog šablona s uneophodni. dodatno, postoje još dva dodatna parametra {{{RawN}}} i {{{LnSty}}}.

Primjer

{{NumBlk|:|<math>y=ax+b</math>|Eq. 3}}

$y=ax+b$

(Eq. 3)

{{NumBlk|:|<math>ax^2+bx+c=0</math>|Eq. 3}}

$ax^{2}+bx+c=0$

(Eq. 3)

{{NumBlk|:|<math>\Psi(x_1,x_2)=U(x_1)V(x_2)</math>|2}}

$\Psi (x_{1},x_{2})=U(x_{1})V(x_{2})$

(2)

{{NumBlk||<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3.5}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

(3.5)

{{NumBlk|:|<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|1}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

(1)

{{NumBlk|::|<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|13.7}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

(13.7)

{{NumBlk|:::|<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|1.2}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

(1.2)

{{NumBlk|:|<math>\mathbf{a}(t)=\lim_{\Delta t \to 0}\frac{\mathbf{v}(t+\Delta t)-\mathbf{v}(t)}{\Delta t}
=\frac{\mathrm{d}\mathbf{v}}{\mathrm{d}t}</math>|Eq. 5}}

$\mathbf {a} (t)=\lim _{\Delta t\to 0}{\frac {\mathbf {v} (t+\Delta t)-\mathbf {v} (t)}{\Delta t}}={\frac {\mathrm {d} \mathbf {v} }{\mathrm {d} t}}$

(Eq. 5)

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=3.5}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

(3.5)

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=3.5|RawN=.}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

3.5

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=<3.5>|RawN=.}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

<3.5>

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=[3.5]|RawN=.}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

[3.5]

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3='''[3.5]'''|RawN=.}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

[3.5]

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=<Big>'''[3.5]'''</Big>}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

([3.5])

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=<Big>'''[3.5]'''</Big>|RawN=.}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

[3.5]

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=<Big>'''(3.5)'''</Big>|RawN=.|LnSty=1px dashed red}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

(3.5)

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=<Big>'''(3.5)'''</Big>|RawN=.|LnSty=3px dashed #0a7392}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

(3.5)

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=<Big>'''[3.5]'''</Big>|RawN=.|LnSty=3px solid green}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

[3.5]

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=<Big>'''[3.5]'''</Big>|RawN=.|LnSty=5px dotted blue}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

[3.5]

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=<Big>'''[3.5]'''</Big>|RawN=.|LnSty=0px solid green}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

[3.5]

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=<Big>'''[3.5]'''</Big>|RawN=.|LnSty=5px none green}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

[3.5]

{{NumBlk|1=:|2=<math>\bold{a}(t)=\frac{d}{dt}\bold{v}(t)</math>|3=<Big>'''[3.5]'''</Big>|RawN=.|LnSty=3px double green}}

${\mathbf {a}}(t)={\frac {d}{dt}}{\mathbf {v}}(t)$

[3.5]

{{NumBlk|:|<math>y=ax+b</math>|Eq. 3|Border=1}}

$y=ax+b$

(Eq. 3)